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| PHP DB Discutii despre lucrul cu baze de date in PHP. |
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15.03.2007
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#1 |
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8-Bit Member
Data înregistrării: 15.03.2007
Mesaje: 2
Rep Power: 6  |
afisare campuri din tabele
ici ar trebui sa fie date
<html> <head> <title>Aici</title> </head> <body> <img src="main_bkg.JPG" width="99" height="50" > <? if( mysql_connect("mysql.lx.ro", "lisp_lx_ro","pass"))print'succes';else print 'eroare'; mysql_select_db("lisp_lx_ro"); if(mysql_select_db("lisp_lx_ro"))print 'connect';else print 'err'; $sql = "SELECT * FROM lisp_lx_ro"; print "<br>".$sql."<br>"; $resursa = mysql_query($sql); print "<br>".$sql."<br>"; print "<table border ='1'>"; while ($row=mysql_fetch_array($resursa)) { print "<tr> <td>".$row['cod']."</td> </tr>"; print "<tr> <td>".$row['nume']."</td> </tr>"; } print "</table>"; ?> mi-am creat baza de date lisp_lx_ro si 2 tabele cod si nume de conectat la baza de date se conecteaza dar de ce nu afiseaza campurile din tabele ? pt ca dc lucrez local pe calclatorul meu imi afiseaza tot. |
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15.03.2007
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#2 |
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8-Bit Member
Data înregistrării: 15.03.2007
Mesaje: 2
Rep Power: 6 |
tot eu
am gresit la crearea campurilor in tabel si la instructiunea Sql :
$sql = "SELECT * FROM lisp_lx_ro"; in loc de $sql = "SELECT * FROM persoane"; |
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